3(2)+5=(3)^2-4x

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Solution for 3(2)+5=(3)^2-4x equation: 



3(2)+5=(3)^2-4x

We move all terms to the left:

3(2)+5-((3)^2-4x)=0

We add all the numbers together, and all the variables

-(3^2-4x)+37=0

We get rid of parentheses

4x+37-3^2=0

We add all the numbers together, and all the variables

4x+28=0

We move all terms containing x to the left, all other terms to the right

4x=-28

x=-28/4

x=-7

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